Android - Làm sao để đọc Rss?

Câu hỏi 1: mình đọc file rss như bên dưới nhưng không đọc được, mong được chỉ giáo.?
Câu hỏi 2: Làm sao để saxparser rss ???

package net.tiennguyen.tiennguyen.docxml;

import android.os.AsyncTask;
import android.os.Bundle;
import android.support.v7.app.AppCompatActivity;
import android.widget.Toast;

import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.net.URL;
import java.net.URLConnection;

public class MainActivity extends AppCompatActivity {

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);

        runOnUiThread(new Runnable() {
            @Override
            public void run() {
                new LoadXML().execute();
            }
        });
    }


    private class LoadXML extends AsyncTask<String,Integer,String>{
        @Override
        protected String doInBackground(String... params) {
            String text = docNoiDung_Tu_URL("http://dantri.com.vn/trangchu.rss");
            return  text;

        }

        @Override
        protected void onPostExecute(String s) {
            Toast.makeText(MainActivity.this,s,Toast.LENGTH_LONG).show();

        }
    }

    private static String docNoiDung_Tu_URL(String theUrl)
    {
        StringBuilder content = new StringBuilder();

        try
        {
            // create a url object
            URL url = new URL(theUrl);

            // create a urlconnection object
            URLConnection urlConnection = url.openConnection();

            // wrap the urlconnection in a bufferedreader
            BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(urlConnection.getInputStream()));

            String line;

            // read from the urlconnection via the bufferedreader
            while ((line = bufferedReader.readLine()) != null)
            {
                content.append(line + "
");
            }
            bufferedReader.close();
        }
        catch(Exception e)
        {
            e.printStackTrace();
        }
        return content.toString();
    }
}