09/10/2018, 18:13
làm sao tuyết rơi từ dưới lên????
Mấy huynh cho đệ hỏi có Code nào làm hình "rơi" trên màn hình không ???
Rơi lên hay xuống gì cũng được
Rơi lên hay xuống gì cũng được
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var no = 15; // image number or falling rate var speed = 3; // the lower the number the faster the image moves var snow = new Array(); snow[0] = "name.gif" snow[1] = "name.gif" snow[2] = "name.gif" var ns4up = (document.layers) ? 1 : 0; // browser sniffer var ie4up = (document.all) ? 1 : 0; var ns6up = (document.getElementById&&!document.all) ? 1 : 0; var dx, xp, yp; // coordinate and position variables var am, stx, sty; // amplitude and step variables var i, doc_width = 800, doc_height = 1800; if (ns4up||ns6up) { doc_width = self.innerWidth; doc_height = self.innerHeight; } else if (ie4up) { doc_width = document.body.clientWidth; doc_height = document.body.clientHeight; } dx = new Array(); xp = new Array(); yp = new Array(); am = new Array(); stx = new Array(); sty = new Array(); j = 0; for (i = 0; i < no; ++ i) { dx[i] = 0; // set coordinate variables xp[i] = Math.random()*(doc_width-50); // set position variables yp[i] = Math.random()*doc_height; am[i] = Math.random()*20; // set amplitude variables stx[i] = 0.02 + Math.random()/10; // set step variables sty[i] = 0.7 + Math.random(); // set step variables if (ns4up) { // set layers if (i == 0) { document.write("<layer name=\"dot"+ i +"\" left=\"15\" top=\"15\" visibility=\"show\"><img src=\""+ snow[j] + "\" border=\"0\"></layer>"); } else { document.write("<layer name=\"dot"+ i +"\" left=\"15\" top=\"15\" visibility=\"show\"><img src=\""+ snow[j] + "\" border=\"0\"></layer>"); } } else if (ie4up||ns6up) { if (i == 0) { document.write("<div id=\"dot"+ i +"\" style=\"POSITION: absolute; Z-INDEX: "+ i +"VISIBILITY: visible; TOP: 15px; LEFT: 15px; width:1;\"><img src=\"" + snow[j] + "\" border=\"0\"></div>"); } else { document.write("<div id=\"dot"+ i +"\" style=\"POSITION: absolute; Z-INDEX: "+ i +"VISIBILITY: visible; TOP: 15px; LEFT: 15px; width:1;\"><img src=\"" + snow[j] + "\" border=\"0\"></div>"); } } if (j == (snow.length-1)) { j = 0; } else { j += 1; } } function snowNS() { // Netscape main animation function for (i = 0; i < no; ++ i) { // iterate for every dot yp[i] -= sty[i]; if (yp[i] < -50) { xp[i] = Math.random()*(doc_width-am[i]-30); yp[i] = doc_height; stx[i] = 0.02 + Math.random()/10; sty[i] = 0.7 + Math.random(); doc_width = self.innerWidth; doc_height = self.innerHeight; } dx[i] += stx[i]; document.layers["dot"+i].top = yp[i]+pageYOffset; document.layers["dot"+i].left = xp[i] + am[i]*Math.sin(dx[i]); } setTimeout("snowNS()", speed); } function snowIE_NS6() { // IE main animation function for (i = 0; i < no; ++ i) { // iterate for every dot yp[i] -= sty[i]; if (yp[i] < -50) { xp[i] = Math.random()*(doc_width-am[i]-30); yp[i] = doc_height; stx[i] = 0.02 + Math.random()/10; sty[i] = 0.7 + Math.random(); doc_width = ns6up?window.innerWidth-5:document.body.clientWidth; doc_height = ns6up?window.innerHeight-5:document.body.clientHeight; } dx[i] += stx[i]; if (ie4up){ document.all["dot"+i].style.pixelTop = yp[i]+document.body.scrollTop; document.all["dot"+i].style.pixelLeft = xp[i] + am[i]*Math.sin(dx[i]); } else if (ns6up){ document.getElementById("dot"+i).style.top=yp[i]+pageYOffset; document.getElementById("dot"+i).style.left=xp[i] + am[i]*Math.sin(dx[i]); } } setTimeout("snowIE_NS6()", speed); } if (ns4up) { snowNS(); } else if (ie4up||ns6up) { snowIE_NS6(); }đệ sẽ dùng thử xem